Which of the following reactions will not pro | vedclass

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Question

(C) Let us analyze each reaction:$(A)$ Nitrobenzene $(C_6H_5NO_2)$ on reduction with $H_2/Pd$ in ethanol gives Aniline $(C_6H_5NH_2)$.$(B)$ Benzoic ac

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Benzonitrile reacting with $Na(Hg)$ in $C_2H_5OH$.

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(C) Let us analyze each reaction:$(A)$ Nitrobenzene $(C_6H_5NO_2)$ on reduction with $H_2/Pd$ in ethanol gives Aniline $(C_6H_5NH_2)$.$(B)$ Benzoic acid $(C_6H_5COOH)$ reacts with hydrazoic acid $(HN_3)$ in the presence of $H_2SO_4$ (Schmidt reaction) to give Aniline $(C_6H_5NH_2)$.$(C)$ Benzonitrile $(C_6H_5CN)$ on reduction with $Na(Hg)/C_2H_5OH$ (Mendius reduction) gives Benzylamine $(C_6H_5CH_2NH_2)$,not Aniline.$(D)$ Benzamide $(C_6H_5CONH_2)$ reacts with $Br_2/NaOH$ (Hofmann bromamide degradation) to give Aniline $(C_6H_5NH_2)$.Therefore,option $(C)$ does not produce Aniline.

Which of the following reactions will not produce "Aniline"?

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